SOLUTION: A radiator contains 6L of a 44% antifreeze mixture. How much pure antifreeze should be added to a mixture that is 52% antifreeze?
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Question 1050369: A radiator contains 6L of a 44% antifreeze mixture. How much pure antifreeze should be added to a mixture that is 52% antifreeze?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A radiator contains 6L of a 44% antifreeze mixture. How much pure antifreeze should be added to a mixture that is 52% antifreeze?
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Add L liters.
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6*44 + L*100 = (6+L)*52
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Might not work if it overfills, tho.
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