SOLUTION: A chemical company makes two brands of antifreeze. The first brand is 55% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 160 gallons of a mixtur

Question 1048933: A chemical company makes two brands of antifreeze. The first brand is
55% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 160 gallons of a mixture that contains 85% pure antifreeze, how many gallons of each brand of antifreeze must be used?
I'm assuming x+y=160 and .55+.95=.85 but the answer doesn't make sense to me.
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = gallons of 55% antifreeze needed
Let = gallons of 95% antifreeze needed
-----------------------
(1)
(2)
-----------------------------------
(2)
(2)
(2)
(2)
----------------------------
Multiply both sides of (1) by
and subtract (1) from (2)
(2)
(1)
---------------------------

and
(1)
(1)
-------------------
40 gallons of 55% antifreeze are needed
120 gallons of 95% antifreeze are needed
--------------------------------------
check:
(2)
(2)
(2)
(2)
(2)
OK

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