SOLUTION: Ref. 1046146: 0.95 = 0.4v + 0.4 0.95 - 0.4 = 0.4v + 0.4 - 0.4 0.55 = 0.4v 0.55 / 0.4 = 0.4v / 0.4 1.375 = v Where am I correct ? Also, I have read that if, an

Question 1046181: Ref. 1046146:
0.95 = 0.4v + 0.4
0.95 - 0.4 = 0.4v + 0.4 - 0.4
0.55 = 0.4v
0.55 / 0.4 = 0.4v / 0.4
1.375 = v
Where am I correct ?
Also, I have read that if, an amount of water, in this case, the amt. of alcohol is diluted, but when alcohol is added, the amt. remains unchanged. Am I on the right track ?

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
0.55 = 0.4v
0.55 / 0.4 = 0.4v / 0.4
1.375 = v
Where am I correct ?
Also, I have read that if, an amount of water, in this case, the amt. of alcohol is diluted, but when alcohol is added, the amt. remains unchanged. Am I on the right track ?
===========================================
A 1 qt. mixture of alcohol and water is 95% alcohol. The mixture is to be reduced to 40% alcohol. Determine amount of distilled water to be added.
--------------
Add W quarts of water
---
1*95 + W*0 = (1 + W)* 40
40W + 40 = 95
40W = 55
W = 11/8 quarts

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