SOLUTION: A photographer wants to mix 16 liters of a 7% acetic acid solution with a 12% solution to get a 9% solution. How many liters of 12% solution must be added?

Question 1045917: A photographer wants to mix 16 liters of a 7% acetic acid solution with a 12% solution to get a 9% solution. How many liters of 12% solution must be added?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
Mixture: one material quantity unknown https://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev
Answer by ikleyn(52786)   (Show Source): You can put this solution on YOUR website!
.
A photographer wants to mix 16 liters of a 7% acetic acid solution with a 12% solution to get a 9% solution.
How many liters of 12% solution must be added?
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Let x be the volume of the 12% solution to be mixed. Then the total volume of the liquid will be (16+x) liters. The amount of pure acetic acid in 16 liters of the 7% solution is 0.07*16. The amount of pure acetic acid in x liters of the 12% solution is 0.12*x. The amount of pure acetic acid in (16+x) liters of the mixture will be (0.07*16 + 0.12*x). The concentration condition for the mixture requires = 0.09*(16+x). It is your equation to solve for x. Simplify it step by step 1.12 + 0.12x = 1.44 + 0.09x, 0.12x - 0.09x = 1.44 - 1.12, 0.03x = 0.32, x = = . Answer. liters of the 12% solution must be added.

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