SOLUTION: How many gallons of a 70​% antifreeze solution must be mixed with 90 gallons of 25​% antifreeze to get a mixture that is 60​% ​antifreeze? Use the​ si
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Question 1035980: How many gallons of a 70% antifreeze solution must be mixed with 90 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method. can you help me do this type proble?
Found 2 solutions by josmiceli, stanbon:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
I don't know what the 6-step method is, but
this is how I do it:
Let = gallons of 70% antifreeze needed
gallons of pure antifreeze in 25% solution
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315 gallons of 70% antifreeze are needed
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check:
OK
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many gallons of a 70% antifreeze solution must be mixed with 90 gallons of 25% antifreeze to get a mixture that is 60% antifreeze? Use the six-step method. can you help me do this type proble?
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Equation::
anti + anti = anti
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0.70x + 0.25*90 = 0.60(x + 90)
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70x + 25*90 = 60x + 60*90
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10x = 35*90
x = 9*35
x = 315 gallons (amt. of 70% solution needed)
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Cheers,
Stan H.
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