SOLUTION: Sandy needs 14 lb of metal with 50 % silver. If Sandy combines one metal with 16 % silver, and another with 78 % silver, how much of each metal does Sandy need?

Question 1033185: Sandy needs 14 lb of metal with 50 % silver. If Sandy combines one metal with 16 % silver, and another with 78 % silver, how much of each metal does Sandy need?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the number of pounds of 16% used, x.
Then the number of pounds of 78% used must be 14-x.
The setup looks like this:
.16x + .78(14-x) = .50(14)
Now solve for x...
.16x + 10.92 - .78x = 7
-.62x = -3.92
x = 6.32 lb of 16%
which means Sandy needs
14-x = 7.68 lb of 78% silver
RELATED QUESTIONS
Sam needs 3 lb of metal with 43% silver. If sam combines one metal with 18% silver, and... (answered by josmiceli)

Dan needs 4 lb of metal with 35 % silver. If Dan combines one metal with 24 % silver,... (answered by jorel1380)

) Sally needs 10 lb of metal with 33 % silver. If Sally combines one metal with 18 %... (answered by josmiceli)

Tom needs 7 pounds of metal with 32% silver. If Tom combines one metal with 25% silver... (answered by josgarithmetic)

Nancy needs 14lb of metal with 31% silver. If nancy combines one metal with 27% silver,... (answered by josgarithmetic)

Jessica needs 12lb of metal with 43% silver. If Jessica combines one metal with 12%... (answered by stanbon)

Sally needs 9lb of metal with 53% silver. If Sally combines one metal with 22% silver,... (answered by josgarithmetic)

sara needs 11lb of metal with 45% silver. if sara combines one metal with 7 % silver, and (answered by ikleyn)

Nancy need 8 pounds of metal with 39% silver. If Nancy combines one metal with 19%... (answered by josgarithmetic)