SOLUTION: how many 20% acid solution should be mixed with 6 oz of 30% acid solution to produce a mixture that is 28% acid? could u make a chart because I like visuals. I want to be able

Question 1032471: how many 20% acid solution should be mixed with 6 oz of 30% acid solution to produce a mixture that is 28% acid?
could u make a chart because I like visuals. I want to be able to use the same concept with other similar mixture problems. Thanks.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how many 20% acid solution should be mixed with 6 oz of 30% acid solution to produce a mixture that is 28% acid?
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Sketch 3 jugs
Start jug has x oz of 20% solution
Second jug as 6 oz of 30% solution
Result jug has (x+6)oz of 28% solution
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Equation:
acid + acid = acid
0.20x + 0.30*6 = 0.28(x+6)
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20x + 30*6 = 28x + 28*6
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8x = 2*6
x = 12/8 = 3/2 oz (amt. of 20% to add)
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Cheers,
Stan H.
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