SOLUTION: an experiment requires mixing a 40% acid solution with a 70% avid solution to create 150 ml of 46% acid solution. how much 40% acid solution and how much 70% acid solution should b
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Question 1029981: an experiment requires mixing a 40% acid solution with a 70% avid solution to create 150 ml of 46% acid solution. how much 40% acid solution and how much 70% acid solution should be used?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Let 
represent the amount of 40% solution. Then the amount of 70% solution must be 
. The amount of pure acid in the 40% solution is then 
and the amount of pure acid in the 70% solution is )
. The amount of pure acid in the 46% solution is )
. Therefore:
\ =\ 0.46(150))
Solve for and then calculate
John
My calculator said it, I believe it, that settles it
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