SOLUTION: How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution?
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Question 1025472: How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How many liters of a 60% acid solution must be mixed with 20% acid solution to get 320 liters of a 50% acid solution?
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Do it like this:
How many liters of a 65% acid solution must be mixed with 10% acid solution to get 320 liters of a 30% acid solution?
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s = amount of 65%
t = amount of 10%
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s + t = 320 (total solution)
65s + 10t = 320*30 (total acid)
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s + t = 320 --> t = 320 - s
65s + 10t = 320*30 = 9600
Sub for t
65s + 10(320-s) = 9600
75s + 3200 = 9600
s = 6400/75
s = 256/3 liters
t = 704/3 liters
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