SOLUTION: A pharmacist wishes to mix a solution that is 5​% Minoxidil. She has on hand 80 ml of a 2​% solution and wishes to add some 7​% solution to obtain the desired 5&
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Question 1024647: A pharmacist wishes to mix a solution that is 5% Minoxidil. She has on hand 80 ml of a 2% solution and wishes to add some 7% solution to obtain the desired 5% solution. How much 7% solution should she add?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
she wants to get a mix of 5% minoxidil.
she has 80 ml of 2% solution of minoxidil.
she has a certain quantity of 7% minoxidil solution on hand that she can use.
let x equal the amount of 7% solution that she has to add.
let y = the total amount of solution that she will wind up with.
you have two equations that need to be solved simultaneously.
they are:
total solution:
80 + x = y
total amount of minoxidil:
.02 * 80 + .07 * x = .05 * y
since y = 80 + x, then replace y with 80 + x in the second equation to get:
.02 * 80 + .07 * x = .05 * (80 + x)
simplify this equation to get:
1.6 + .07 * x = 4 + .05 * x
subtract 1.6 from both sides of the equation and subtract .05 * x from both sides of the equation to get:
.07 * x - .05 * x = 4 - 1.6
simplify to get .02 * x = 2.4
divide both sides of the equation by .02 to get x = 2.4 / .02 = 120.
she would need 120 ml of the 7% solution to get a 5% solution.
the total number of mls would be 80 + 120 = 200.
the total amount of minoxidil would be .02 * 80 + .07 * 120 = 1.6 + 8.4 = 10.
the percent of minoxidil in the final solution would be 10 / j200 = .05 * 100 = 5%.
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