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A glass tube 1.5 m tall is filled with liquid of density 1080 . What pressure exerted on the base of the tube if the atmospheric pressure is 101 kpa? [g=10 m/s]
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The pressure a column of liquid exerts on the bottom is
P = ,
where is the liquid density, g is acceleration due to gravity and h is the height of the column of the liquid.
So, in your case P = 1080*10*1.5 = 16200 kpa.
To account for the atmospheric pressure add it (101 kpa).
But keep in mind that the same atmospheric pressure acts to the bottom from the outside
(until special measures are taken to isolate the bottom from the atmosphere).