Let the number of kgs. of Alloy1 be x Let the number of kgs. of Alloy2 be y Number Type Number Percent of kg of of kg which is of copper coin of metal copper in each ------------------------------------------- Alloy1 x 0.30 0.30x Alloy2 y 0.60 0.60y ------------------------------------------- mixture 80 0.48 0.48(80) The first equation comes from the second column.x + y = 80 The second equation comes from the last column. 0.3x + 0.6y = 0.48(80) 0.3x + 0.6y = 38.4 Get rid of decimals by multiplying every term by 10: 3x + 6y = 384 So we have the system of equations: . We solve by substitution. Solve the first equation for y: x + y = 80 y = 80 - x Substitute (80 - x) for y in 30x + 60y = 3840 3x + 6(80 - x) = 384 3x + 480 - 6x = 384 -3x + 480 = 384 -3x = -96 x = 32 = the number of kg. of Alloy1. Substitute in y = 80 - x y = 80 - 32 = 48 kg. of Alloy2. Edwin