Let amount of QXJ solution to add, be q
It's best to change the fractions to decimals.
In so doing,becomes: .5; becomes: .75, becomes .6, and we get:
.5(1) + .75(q) = .6(1 + q)
.5 + .75q = .6 + .6q
.75q - .6q = .6 - .5
.15q = - .1
q, or amount of QXJ solution to add = .1/.15, orL