SOLUTION: How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution.

Question 1005187: How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution.
Found 2 solutions by Boreal, stanbon:
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x liters of 20%
.20x+30(.50)=(x+30)(.40)
.20x+15=.40x + 12
-.20x= -3
x=15 liters
15*(.20 pure acid)=3 liters
30*(.50 pure acid)=15 liters
That is 18 liters pure acid
That is 45 liters solution *0.45 pure acid=18 liters.
The answer is 15 liters

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution.
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Equation:
acid + acid = acid
0.20x + 0.50*30 = 0.40(x+30)
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20x + 50*30 = 40x + 40*30
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-20x = -10*30
x = 15 liters (amt. of 20% solution needed)
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Cheers,
Stan H.
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