SOLUTION: A solution of 60% vinegar is to be mixed with a solution of 25% vinegar to form 245 liters of a 43% solution. How many liters of the 60% solution must be used?
176 liters
136 l
Algebra.Com
Question 1003662: A solution of 60% vinegar is to be mixed with a solution of 25% vinegar to form 245 liters of a 43% solution. How many liters of the 60% solution must be used?
176 liters
136 liters
142 liters
126 liters
Answer by josgarithmetic(39621) (Show Source): You can put this solution on YOUR website!
Just one variable to solve two-part mixture problem
Q # 1003662 and 1003661 work the same way.
RELATED QUESTIONS
A solution of 77% vinegar is mixed with a solution of a 25% vinegar to form 312 liters of (answered by stanbon)
A solution of 49% vinegar is to be mixed with a solution of 32% vinegar to form 153... (answered by nerdybill)
a solution of 63% vinegar is to be mixed with a solution of 28% vinegar to form 70 liters (answered by stanbon)
how many millilitres of vinegar must be added to 20 millilitres of a 10%-vinegar... (answered by checkley79)
I don't understand how to create an algebraic formula to answer this question:
A... (answered by stanbon)
How many liters of pure water must be mixed with 1 liter of a 5% vinegar solution to give (answered by macston,Alan3354)
If 4 liters of a 15% vinegar solution is mixed with x liters of a 30% vinegar solution,... (answered by amoresroy,math_tutor2020)
how much of a 15 vinegar solution should be added to a 35% vinegar soultion to make 12... (answered by josgarithmetic)
how much pure (100%) vinegar and 5% vinegar must be mixed to obtain 50oz of a 24%... (answered by oberobic)