Tutors Answer Your Questions about Mixture Word Problems (FREE)
Question 571349: Wilbur wants to make a 8% acid solution.
He has already poured 3 gal. of pure water into a beaker.
How many gal. of a 14% acid solution must he add to this to create the desired mixture?
Answer by Alan3354(21549)   (Show Source):
You can put this solution on YOUR website!Wilbur wants to make a 8% acid solution.
He has already poured 3 gal. of pure water into a beaker.
How many gal. of a 14% acid solution must he add to this to create the desired mixture?
-----------------
14*g + 3*0 = (g + 3)*8
14g = 8g + 24
g = 4 gallons of 14%
Question 571292: Perry wants to make 10 gal. of a 58% sugar
solution by mixing together a 70% sugar solution
and a 40% sugar solution. How much of the 70%
sugar solution must he use?
Answer by lwsshak3(2907) (Show Source):
You can put this solution on YOUR website!Perry wants to make 10 gal. of a 58% sugar
solution by mixing together a 70% sugar solution
and a 40% sugar solution. How much of the 70%
sugar solution must he use?
**
let x=gal of 70% solution Perry must use
10-x=gal of 40% solution Perry must use
..
70%x+40%(10-x)=58%(10)
.7x+.4-.4x=5.8
.3x=5.4
x=18
ans:
gallons of 70% solution Perry must use=18
Question 571267: If I had to buy 100 chickens for $100 where
Roster=$5
Hens=$1
Bitties=$.05
How many of each will I have to buy to equal 100 chickens @$ 100
Answer by ankor@dixie-net.com(12681)  (Show Source):
You can put this solution on YOUR website!If I had to buy 100 chickens for $100 where
Roster=$5
Hens=$1
Bitties=$.05
How many of each will I have to buy to equal 100 chickens @$ 100
:
Total chicken equation
r + h + b = 100
total cost equation
5r + 1h + .05b = 100
:
This does not seem to work out, no integer solutions, perhaps you meant:
:
Roster=$5
Hens=$1
Bitties=$.50
then
Total chicken equation
r + h + b = 100
total cost equation
5r + 1h + .5b = 100
:
Subtract the 1st equation from the above equation
5r + 1h + .5b = 100
1r + 1h + 1b = 100
-------------------eliminates h
4r - .5b = 0
4r = .5b
r =  b
You can see in order to have an integer solution, b = 8
r = (8)
r = 1 rooster, 8 bitties
Find h
1 + h + 8 = 100
h = 100 - 9
h = 91 hens
:
Summarize: 1 rooster, 91 hens, 8 bitties
Check
5(1) + 1(91) + .5(8) =
5 + 91 + 4 = $100
Question 571243: By weight one alloy has 40% Aluminum, 38% Copper and the rest Cadmium. The second alloy has 52%, 20% and 28% Aluminum, Copper, and Cadmium respectively. The Aluminum, Copper, and Cadmium content of the third alloy is 61%, 12% and 27% respectively. How much of each alloy must be mixed to produce 1000 Lbs of alloy with the following content of 50.2% Aluminum, 23.8% Copper and 26% Cadmium? I am completely stumped on how to figure this one out. Can someone help Please?
Answer by scott8148(5879)  (Show Source):
You can put this solution on YOUR website!let x = amount of 1st alloy , y = amount of 2nd alloy , and z = amount of 3rd alloy
you are given the amounts of the components in the final alloy
___ Al = (50.2%)(1000) = 502 lb
___ Cu = (23.8%)(1000) = 238 lb
___ Cd = (26%)(1000) = 260 lb
.4x + .52y + .61z = 502
.38x + .2y + .12z = 238
.22x + .28y + .27z = 260
solve the system of equations to find the amounts of the three alloys
you might want to think about Cramer's Rule
Question 571231: How many gallons of a 5% salt solution must be mixed with 63 gallons of a 15% salt solution to make a 12% salt solution?
Answer by josmiceli(6769)  (Show Source):
Question 571196: How many litres of 35% sugar solution should be added to a 17% sugar solution to obtain 72 litres of 25% sugar solution?
Answer by mrjunecarlo1095@ymail.com(6)  (Show Source):
You can put this solution on YOUR website!So first,
.35(x) + .17(72-x) = .25(72)
by multiplication (distribution property of real numbers) ,
we will get,
(.35x) + (12.24-.17x) = 18
.18x + 12.24 =18
18x=18-12.24
.18x= 5.76
so x= 32
35% sugar solution needs 32 liters and 17% sugar solution needs 40 % in order to obtain 25% sugar solution in 72 liters.
Question 571063: a solution of 63% vinegar is to be mixed with a solution of 28% vinegar to form 70 liters of a 47% solution. How many liters of the 63% solution be used?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!a solution of 63% vinegar is to be mixed with a solution of 28% vinegar to form 70 liters of a 47% solution. How many liters of the 63% solution be used?
------------------------------
Equation:
0.63x + 0.28(70-x) = 0.47*70
------
Multiply thru by 100 to get:
63x + 28*70 - 28x = 47*70
25x = 19*70
x = 53.2 liters (amt of 63% solution needed)
===========================
Cheers,
Stan H.
==================
Question 571049: If 35 liter of milk cost $28.00, what is teh price per liter?
Answer by nyc_function(2626)  (Show Source):
Question 570945: Wendy took a trip from city A to city B, a distance of 340 mi. She traveled part of the way by bus, which arrived at the train station just in time for Wendy to complete her journey by train. The bus averaged 40 mi/h, and the train averaged 120 mi/h. The entire trip took 4.5h. How long did Wendy spend on the train?
Answer by lwsshak3(2907) (Show Source):
You can put this solution on YOUR website!Wendy took a trip from city A to city B, a distance of 340 mi. She traveled part of the way by bus, which arrived at the train station just in time for Wendy to complete her journey by train. The bus averaged 40 mi/h, and the train averaged 120 mi/h. The entire trip took 4.5h. How long did Wendy spend on the train?
**
let x=distance Wendy traveled on the bus
340-x=distance Wendy traveled on the train
Travel time=distance/speed
..
x/40+(340-x)/120=4.5
LCD=120
3x+340-x=4.5*120
2x=540-340=200
x=100
(340-x)/120=240/120=2
ans:
hours Wendy spent on the train=2
Question 570802: How many kilos of tea worth Rs.72 per kg should be mixed with 10kg of tea worth Rs.90 per kg to produce a mixture which will cost Rs.78 per kg
Answer by mananth(10539)  (Show Source):
You can put this solution on YOUR website!---------------- Price ---------------- quantity
Tea type I 90 ----------------10 pounds
Tea type II 72 ----------------x pounds
Mixture 78 ---------------- 10+x pounds
sum of individual components = quantity in mixture
90*10+72x=78(10 +x)
900+72x =780+78 x
72x -78 x=-120
-6x=-120
x= -120 / -6
x= 20
20 pounds of Tea type II costing Rs. 72 has to be added
m.ananth@hotmail.ca
Question 570788: I am stuck on this math word problem.
It states: you need to make a 600mL solution of hydrogen peroxide. You find a bottle of 80mL of 30% hydrogen peroxide. How much mL of 30% hydrogen peroxide would you add to how many mL of water to make exactly 600mL of hydrogen peroxide?
I would greatly appreciate any help!
Thanks
Answer by KMST(576)  (Show Source):
You can put this solution on YOUR website!You left out some information. You need to make a solution of hydrogen peroxide, but you left out the concentration you need. I'll pretend you need a 4% solution.
In analytical chemistry we base dilutions calculations on the fact that the amount of the substance we are diluting is the same before and after adding water (or other solvent), so we say that volume times concentration (equal or proportional to amount of substance in some unit) is the same before and after diluting.
You will need x mL of the 30% peroxide solution to make 600 mL of 4% solution
(600 mL)(4%)=(30%)(x mL)
dividing both sides by 30%
(600 mL)(4%)/(30%)= x mL
x mL = 80 mL
So for 600 mL of 4% solution you would use the entire 80 mL of 30% solution you have, and would add water to make the volume up to 600 mL.
You would need 600 mL - 80 mL = 520 mL water.
NOTE: The 30% peroxide solution is about the most concentrated hydrogen peroxide solution you can get (although once I got a 35% solution in the lab). It burns skin (it turn white and itch-burns badly), and discolors many materials. Do not try this at home.
Question 570766: How many grams of salt need to be added to 60 grams of a 20% salt solution in order to increase the salt content to 25%?
I tried this question on one of my tests.. I failed the test because these types of problems were half the test.. I do not know how to do it. The answer is apparently four. I just need to know how to do it.
Thank you!
Answer by Maths68(1140)  (Show Source):
You can put this solution on YOUR website!Solution A
Amount = x grams
Concentration =100% =1 (It is pure salt)
Solution B
Amount = 60 grams
Concentration =20% = 0.2
Resultant Solution
Amount = (60+x) grams
Concentration =25%=0.25
[Amount Solution A * Concentration A] + [Amount Solution B * Concentration of B] = Amount of Resultant * Concentration of resultant
(x)(1)+(60)(0.2)=(60+x)(0.25)
x+12=15+0.25x
x-0.25x=15-12
0.75x/0.75=3/0.75
x=4
We need to add 4 grams of salt to increase the salt content to 25%
Question 570639: shamrock has 900 pounds of milk that is 2% butterfat, how much butterfat do they have to add to raise the butterfat content to 8%?
Answer by mananth(10539) (Show Source):
You can put this solution on YOUR website! percent ---------------- quantity
Milk 2 ---------------- 900 pounds
Butter fat 100 ---------------- x pounds
Mixture 8 ---------------- 900 + x pounds
sum of individual components = quantity in mixture
2*900+100x=8(900+x)
1800+100x=7200 +8x
100x-8x =5400
92x=5400
x= 5400 / 92
x= 58.7
58.7 pounds of Butter fat has to be added
Question 570433: Joe has a 15 gallon fish tank. The tank currently has 7 quarts of water in it. How many pints of water are needed to fill it all the way up?
Answer by Alan3354(21546) (Show Source):
You can put this solution on YOUR website!Joe has a 15 gallon fish tank. The tank currently has 7 quarts of water in it. How many pints of water are needed to fill it all the way up?
------------
1 gallon = 4 quarts
1 quart = 2 pints
----
An unfortunate system.
Question 570085: I do not understand how to work these problems, I am pretty good at algebra but i do not understand what formula to use or how to work through them, any help is appreciated.
The radiator in a certain make of car needs to contain 70 liters of 40% antifreeze. the radiator now contains 70 liters of 20% antifreeze. How many liters of this solvent must be drained and replaced with 00% antifreeze to get the desired strength?
Answer by KMST(576) (Show Source):
You can put this solution on YOUR website!If the radiator has 20% antifreeze now and it needs 40%, you may need to replace some of the liquid with 100% antifreeze (not 00%, which I think is some kind of typo).
This kind of problem requires that you do some accounting of both, the total volume, and the amount of the substance of interest that is mixed in.
The total volume you need is 70 L.
The total amount of antifreeze that you need in those 70 L is
 L = 28 L
If you remove  L of what is in the radiator now, and replace them with L of 100% antifreeze, you expect to have 70 L again in the end.
The final amount of antifreeze in there will be
 L from the  L of 20% antifreeze solution not removed, plus
L that were added, so the total (as a function of ) is
 L
So we need to find the that will make that the needed 28 L of antifreeze calculated above.
 -->  -->  -->  L
Question 570065: How do I set this type of word problem up? Thanks
Joe's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Joe $5.40 per pound, and type B coffee costs $4.20 per pound. This month's blend used twice as many pounds of type B coffee as type A, for a total cost of $372.60 . How many pounds of type A coffee were used?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!Joe's Coffee Shop makes a blend that is a mixture of two types of coffee.
Type A coffee costs Joe $5.40 per pound, and type B coffee costs $4.20 per pound. This month's blend used twice as many pounds of type B coffee as type A, for a total cost of $372.60 . How many pounds of type A coffee were used?
-----
Equations:
Quantity Eq:::B = 2A
Value Eq:::::5.4A + 4.2B = 372.6
----
Substitute for "B" and solve for "A":
5.4A + 4.2(2A) = 372.6
------
5.4A + 8.4A = 372.6
13.8A = 372.6
A = 27 lbs (amt. of Type A coffee needed)
========
Cheers,
Stan H.
=============
Question 569918: How much of a brand a fruit punch ( 35 % fruit punch ) must be mixed with 8 litter of brand b
fruit punch(20% fruit juice) to create a mixture containing 27% fruit ?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!How much of a brand a fruit punch ( 35 % fruit punch ) must be mixed with 8 liter of brand b fruit punch(20% fruit juice) to create a mixture containing 27% fruit ?
---
Equation:
0.35x + 0.20*8 = 0.27(x+8)
------
Multiply thru by 100 to get:
35x + 20*9 = 27x + 27*8
8x = 7*8
x = 7 liters (amt of 35% juice needed)
=============================================
Cheers,
Stan H.
Question 569509: A coffee distributor needs to mix a(n) Kona coffee blend that normally sells for $8.80 per pound with a Kenya coffee blend that normally sells for $14.00 per pound to create 100 pounds of a coffee that can sell for $13.17 per pound. How many pounds of each kind of coffee should they mix?
Answer by josmiceli(6769) (Show Source):
You can put this solution on YOUR website!Let  = pounds of Kona coffee needed
Let  = pounds of Kenya coffee needed
given:
(1) 
(2) 
------------------------------
(2) 
(2) 
Multiply both sides of (1) by 
and subtract (1) from (2)
(2)
(1) 
and
(1) 
(1) 
15.962 pounds of Kona coffee are needed
84.038 pounds of Kenya coffee are needed
check:
(2)
(2) 
(2) 
(2) 
close enough
Question 569512: You are mixing a 10% hydrochloric acid solution with 1% hydrochloric acid solution to make 12 L of a 4.5% solution. How much of each original solution should you use? HELP IM FAILING AT THIS QUESTION.
Answer by josmiceli(6769) (Show Source):
You can put this solution on YOUR website!Let = liters of 10% solution needed
Let = liters of 1% solution needed
 = liters of h. acid in 10% solution
 = liters of h. acid in 1% solution
given:
(1) 
(2) 
----------------------------
(2) 
(2) 
(2) 
Subtract (1) from (2)
(2)
(1) 
and, since
(1)
(1) 
(1) 
(1) 
4.667 liters of 10% solution are needed
7.333 liters of 1% solution are needed
check:
(2)
(2) 
(2) 
(2) 
(2) 
OK- error due to rounding off
Question 569515: A train route goes from city a to city C Before arriving at city C, the train stops at city B. the train take 9 hours to travel 472 miles from city a to city B. At this rate how long does it take the train to travel the 1578 miles from city b to city c?
Answer by lwsshak3(2907) (Show Source):
You can put this solution on YOUR website!A train route goes from city a to city C Before arriving at city C, the train stops at city B. the train take 9 hours to travel 472 miles from city a to city B. At this rate how long does it take the train to travel the 1578 miles from city b to city c?
**
rate of speed of train=472 mi/9 hrs=472/9 mph
For the 1578 miles from city b to city c,
travel time=distance/speed=1578/(472/9)≈30 hrs
ans:
Time it takes to travel the 1578 miles from city b to city c=30 hrs
Question 569413: What is the volume of a 60% alcohol solution that contains 90cc of alcohol? How do you set it up and solve it? Thanks for your time.
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!What is the volume of a 60% alcohol solution that contains 90cc of alcohol?
-----
Let the volume be "x":
Equation:
0.60x = 90cc
---
x = 90/0.60 = 150 cc
========================
Cheers,
Stan H.
Question 569193: can you show me a step by step answer to this word problem?
Milk that is 4% butterfat is mixed with milk that is 1% butterfat to obtain 18 gallons of milk that is 2% butteraft. How many gallons of each type of milk are needed?
i know the answer is 6 gallons of 4% and 12 gallons of 1% but can you please show me the work of how to get this.
Answer by lwsshak3(2907) (Show Source):
You can put this solution on YOUR website!can you show me a step by step answer to this word problem?
Milk that is 4% butterfat is mixed with milk that is 1% butterfat to obtain 18 gallons of milk that is 2% butteraft. How many gallons of each type of milk are needed?
**
let x=gallons of 4% butterfat milk needed
4%x=amount of butterfat in x gallons of milk
18-x=gallons of 1% butterfat milk needed
1%(18-x)=amount of butterfat in 18-x gallons of milk
2%*18=amount of butterfat in 18 gallons of milk
..
4%x+1%(18-x)=2%18
.04x+.18-.01x=.36
.03x=.18
x=6
18-6=12
ans:
gallons of 4% butterfat milk needed=6
gallons of 1% butterfat milk needed=12
Question 569166: How many ounces of vermouth containing 10% alcohol should be added to 20 ounces of gin containing 60% alcohol to make a pitcher of martinis that contains 30% alcohol?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!How many ounces of vermouth containing 10% alcohol should be added to 20 ounces of gin containing 60% alcohol to make a pitcher of martinis that contains 30% alcohol?
------
Equation:
alcohol + alcohol = alcohol
0.10x + 0.60*20 = 0.30(x+20)
--------
Multiply thru by 100:
10x + 60*20 = 30x +30*20
20x = 30*20
x = 30 oz (amt. of 10% vermouth needed)
==========================================
Cheers,
Stan H.
================
Question 569130: it is necessary to have a 70% antifreeze solution in a radiator of a certain car. the radiator now has 20 ml of 60% solution. how much of this solution should be drained and replaced with 100% antifreeze to get the desired strength
Answer by lwsshak3(2907) (Show Source):
You can put this solution on YOUR website!it is necessary to have a 70% antifreeze solution in a radiator of a certain car. the radiator now has 20 ml of 60% solution. how much of this solution should be drained and replaced with 100% antifreeze to get the desired strength.
**
x=ml of 60% solution to be drained and replaced with 100% antifreeze
20-x=ml of 60% solution remaining
..
60%(20-x)+100%x=70%*20
12-0.6x+x=14
0.4x=2
x=5 ml
ans:
ml of 60% solution to be drained and replaced with 100% antifreeze=5
Question 568850: How many ounces of a solution that is 90% alcohol need to be mixed with 5 ounces of a solution that is 50% alcohol in order to obtain a solution that is 80% alcohol?
I have tried a formula: 5(.50) + x(.90) = .80, but the answer yields a negative amount of ounces which is not possible.
Answer by josmiceli(6769) (Show Source):
You can put this solution on YOUR website!Let  = ounces of 90% solution needed
 = ounces of alcohol in 90% solution
 ounces of alcohol in 50% solution
given:
15 ounces of 90% solution are needed
check answer:
OK
Question 568487: The Number 120 is 15% of what number?
Found 2 solutions by xoapplex, issacodegard:
Answer by xoapplex(2) (Show Source):
Answer by issacodegard(60)  (Show Source):
Question 568743: How many Liters of pure water should be mixed with a 17-L solution of 60% acid to produce a mix that is 80% water?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!How many Liters of pure water should be mixed with a 17-L solution of 60% acid to produce a mix that is 80% water?
------
Equation:
water + water = water
1*x + 0.40*17 = 0.80(x+17)
----
Multiply thru by 100 to get:
100x + 40*17 = 80x + 80*17
20x = 40*17
x = 2*17 = 34 liters (amt. of water needed)
================================
Cheers,
Stan H.
==============
Question 568648: A market sells coffee from Brazil for $3 per pound and coffee from colombia for $4 per pound. How many pounds of each should be used in order to sell the blend of 100 pounds for $3.50 per pound?
Answer by Alan3354(21546) (Show Source):
You can put this solution on YOUR website!A market sells coffee from Brazil for $3 per pound and coffee from colombia for $4 per pound. How many pounds of each should be used in order to sell the blend of 100 pounds for $3.50 per pound?
-------------
$3.50 is the average, so it's equal amounts.
Question 568488: How many liters of pure antifreeze (100% solution) must be added to 30 liters of a 15% antifreeze solution to get a 40% antifreeze solution?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!How many liters of pure antifreeze (100% solution) must be added to 30 liters of a 15% antifreeze solution to get a 40% antifreeze solution?
---
alcohol + alcohol = alcohol
----
1*x + 0.15*30 = 0.40(x+30)
----
Multiply thru by 100 to get:
100x + 15*30 = 40*x + 40*30
60x = 25*30
x = (1/2)25 = 12.5 liters (amt. of pure antifreeze needed)
============================================================
cheers,
Stan H.
Question 568328: You need to make 5 liters of a 12% acetic acid solution. Your lab stocks 5% and 20% acetic acid solutions. How many liters of each stock solution should you mix to make 5 liters of a 12% acetic acid solution?
Answer by mananth(10539) (Show Source):
You can put this solution on YOUR website!----------------- percent ---------------- quantity
Acetic Acid type I 5 ----------------x liters
Acetic acid type II 20 ----------------5-x liters
Mixture 12.00% ---------------- 5
5x+20(5-x)=12*5
5x+100- 20x=60
5x-20x= 60-100
-15x=-40
/-15
x=2.67 liters 5.00% Acetic Acid type I
2.33 liters 20.00% Acetic acid type II
m.ananth@hotmail.ca
Question 568250: ken is mixing fruit punch, it is suppose to be 30% orange juice. So far, ken has mixed two pints of cranberry juice, one pint of orange juice, amd one pint of ginger ale, how much orange juice needs to be added?
Answer by lwsshak3(2907) (Show Source):
You can put this solution on YOUR website!ken is mixing fruit punch, it is suppose to be 30% orange juice. So far, ken has mixed two pints of cranberry juice, one pint of orange juice, amd one pint of ginger ale, how much orange juice needs to be added?
**
let x=pint of orange juice to be added
Originally, orange juice was 25% or 1/4 of the mixture:
To change the mixture to 30%, we must add x pints of orange juice:
(1+x)/(4+x)=30%=.3
1+x=1.2+.3x
.7x=.2
x=2/7
ans:
orange juice needs to be added=2/7 pints
Question 568264: You want 14L of fruit punch that is 10% juice. at the store, you find punch that it 15% juice and punch that is 8% juice. how much of each should you purchase?
Answer by mananth(10539) (Show Source):
You can put this solution on YOUR website!-----------------percent----------------quantity
punch Type I 15 ----------------x liters
Punch type II 8 ----------------14-xliters
Mixture 10.00 ---------------- 14
15x+8(14-x)=10*14
15x+112 -8x=140
15x-8x=140-112
7x=28
/7
x=4liters 15.00% punch Type I
10 liters 8.00% Punch type II
m.ananth@hotmail.ca
Question 568267: A sum of $1350 is to be divided between two people in the ratio of 7 to 8. How much does each person receive?
Answer by mananth(10539) (Show Source):
You can put this solution on YOUR website!$ 1350 is to be divided in the ratio of 7:8
It means one person gets 7 parts of $1350
and another gets 8 parts of $1350
7+8 = 15 parts make up $1350
7/15 is what the first person gets
7/15 * 1350
=7*90
=$630
8/15 * 1350= 90*8= 720
720+630= 1350
Question 567959: a pharmacist has a 45% acid solution and a 35% acid solution. How many liters of it must be mixed to form 80 liters of a 40% acid solution?
Answer by Alan3354(21546) (Show Source):
You can put this solution on YOUR website!a pharmacist has a 45% acid solution and a 35% acid solution. How many liters of it must be mixed to form 80 liters of a 40% acid solution?
------------
40 is the average of 45 & 35, so it's equal amounts.
Question 567911: How many pounds of sunflower seed ($.70/lb) must be mixed with raisins & nuts ($1.90/lb) to form 40 pounds of a mixture to sell at $1.00/lb?
Answer by mananth(10539) (Show Source):
You can put this solution on YOUR website!----------------- price ----------------quantity
sunflower seeds 0.7 ----------------x pounds
Raisins & nuts 1.9 ----------------40-x pounds
Mixture 1.00 ---------------- 40
0.7x+1.9(40-x)=1*40
0.7x+76-1.9x=40
0.7x-1.9x=40-76
-1.2x =-36
/ -1.2
x=30 pounds $0.70 sunflower seeds
10 pounds $1.90 Raisins & nuts
m.ananth@hotmail.ca
Question 567850: P1V1/T1=P2V2/T2 solve for V2 (Chemistry)
Answer by jim_thompson5910(21667) (Show Source):
Question 567784: what is defined as the number of parts per hundred. is the answer percentage or ratio or proportion or expression
Answer by richard1234(4789)  (Show Source):
Question 567775: A pharmacist wishes to mix a solution that is 4% Minoxidil. She has on hand 100ml of 3% solution and wishes to add some 6% solution to obtain the desired 4% solution. how much 6% solution should she add?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!A pharmacist wishes to mix a solution that is 4% Minoxidil. She has on hand 100ml of 3% solution and wishes to add some 6% solution to obtain the desired 4% solution. how much 6% solution should she add?
---------
Equation:
mino + mino = mino
0.03*100 + 0.06x = 0.04(100+x)
Multiply thru by 100 to get:
3*100 + 6x = 4*100 + 4x
2x = 100
x = 50ml (amt of 6% solution needed)
-----------------
Cheers,
Stan H.
================
Question 567763: a tank contains 60 gallons of 50% solution of glycerine and water. what volume of water must be added to the solution to reduce the glycerine concentration to 12%?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!a tank contains 60 gallons of 50% solution of glycerine and water. what volume of water must be added to the solution to reduce the glycerine concentration to 12%?
------
Equation:
glyc + glyc = glyc
0.50*60 + 0*x = 0.12(60+x)
--------
multiply thru by 100 to get:
50*60 = 12*60 + 12x
12x = 38*60
x = 38*5
x = 190 gallons (amt. of water to add)
============================================
Cheers,
Stan H.
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Question 567616: A Chemist needs 120 milliliters of a 21% solution but only has 3% and 27% solutions available. Find how many milliliters of 27% solution should be used to the desired solution.
Answer by Alan3354(21546) (Show Source):
You can put this solution on YOUR website!A Chemist needs 120 milliliters of a 21% solution but only has 3% and 27% solutions available. Find how many milliliters of 27% solution should be used to the desired solution.
-----------------
t = amount of 3%
s = amount of 27%
----
t + s = 120
3t + 27s = 120*21
----
Can you do the rest?
Question 567512: A jeweler has 5 rings, each weighing 16 g, made of an alloy of 15% silver and 85% gold. She decides to melt down the rings and add enough silver to reduce the gold content to 80%. How much silver should she add?
Answer by stanbon(48502) (Show Source):
You can put this solution on YOUR website!A jeweler has 5 rings, each weighing 16 g, made of an alloy of 15% silver and 85% gold. She decides to melt down the rings and add enough silver to reduce the gold content to 80%. How much silver should she add?
------
Equation:
silver + silver = silver
0.15*5*16 + 1*x = 0.20(80+x)
----
Multiply thru by 100 to get:
15*80 + 100x = 20*80 + 20x
80x = 5*80
x = 5 grams of silver (amt. of silver to be added)
=========================================================
Cheers,
Stan H.
============
Question 567513: What quantity of a 55% acid solution must be mixed with a 35% solution to produce 600 mL of a 45% solution?
Answer by mananth(10539) (Show Source):
You can put this solution on YOUR website!----------------- percent ---------------- quantity
Acid type I 55----------------x ml
Acid type II 35----------------600- x ml
Mixture 45.00% ----------------600
55x+35(600-x)= 45*600
55x+ 21000-35x=27000
55x-35x =27000-21000
20x= 6000
/ 20
x= 300ml 55.00% Acid type I
300ml 35.00% Acid type II
m.ananth@hotmail.ca
Question 567498: Phyllis invested $10,000, a portion earning a simple interest rate of 3 1/5%
per year and the rest earning a rate of 3% per year. After 1 year the total interest earned on these investments was $312. How much money did she invest at each rate?
Answer by mananth(10539) (Show Source):
You can put this solution on YOUR website!Investment Part I 3.50% per annum ----x
Investment part II 3.00% per annum ----y
The sum of the investments is $10,000.00
The sum of individual interests = $312.00
x+y= 10000 ------------------------1
3.50%x+ 3.00%y =$312.00
Multiply by 100
3.5x+3y =$31,200.00 --------2
Multiply (1) by -3.5
we get
-3.5x -3.5y= -35000.00
Add this to (2)
0x-0.5y =-$3,800.00
divide by-0.5
y = $7,600.00 investment at 3.00%
Balance $2,400.00 investment at 3.50%
CHECK
$2,400.00 @ 3.50% $84.00
$7,600.00 @ 3.00% $228.00
Total -------------------- $312.00
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