Lesson Word problems on reversing digits of numbers

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Word problems on reversing digits of numbers


Problem 1

Sum of the digits of a two digit number is  10.  When we interchange the digits,  it is found that the resulting number is greater than the original number by  36.
Find the number.

Solution

Let  a  and  b are the digits of your number  n,  so that  n = 10a + b.

The number after interchanging digits is  10b + a.

Then you have the system of two equations for the unknowns  a  and  b:

system%28a%2Bb+=+10%2C%0D%0A%0D%0A%2810b+%2Ba%29+-+%2810a+%2B+b%29+=+36%29.

Now,  simplify it:

system+%28a%2Bb=+10%2C%0D%0A%0D%0A9b+-+9a+=+36%29.

Simplify it one more time:

system+%28a%2Bb=+10%2C%0D%0A%0D%0Ab+-+a+=+4%29.

Solve it.

The solution is   b=7,  a=3.

Hence,  the number is  10a + b = 10*3+7 = 37.

Answer.  37.


Problem 2

When a two-digit number is divided by the product of the two digits,  the quotient is  2.
If  27  is added to the number,  the original number turns into a new number with the digits being swapped around.  Find the number.

Solution

Let  a  and  b  be the first  (the left)  and the second  (the right)  digit of the number respectively,  so that the number is  10a + b.

The first condition says that  %2810a+%2B+b%29%2F%28ab%29 = 2,   or

10a + b = 2ab.         (1)

The number with swapped digits is  10b + a, so the second condition says that

10a + b + 27 = 10b + a,   or   9a - 9b = -27,   or   a-b = -3.

So,  we have a system of two equations

system%2810a+%2B+b+=+2ab%2C%0D%0Aa-b+=+-3%29.

Express  b  from the last equation,  b = a + 3,  and substitute it into the previous equation.  You will get

10a + a + 3 = 2a*(a+3),   or

2a%5E2 - 5a - 3 = 0.

Solve this quadratic equation using the quadratic formula.  You will get the roots  a%5B1%5D = 3  and  a%5B2%5D = -1%2F2.
The negative root doesn't suit,  because we are looking for the digit,  which should be non-negative integer less than 10.  The root  a%5B1%5D = 3  is good.

So,  the number is  36.

Please check yourself that this number satisfies all conditions of the problem.

Answer.  36.


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