SOLUTION: A 173 inch long pipe is cut into three pieces such that the second piece is six inches more than the first piece, and the third piece is nineteen inches more than eight times the s
Algebra.Com
Question 991250: A 173 inch long pipe is cut into three pieces such that the second piece is six inches more than the first piece, and the third piece is nineteen inches more than eight times the second piece.
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
Hi there,
Make first piece = 'x'
Second piece = x + 6
Third piece = 19 + 8(x + 6)
Add all pieces together:
x + x + 6 + 19 + 8(x + 6)
x + x + 6 + 19 + 8x + 48
= 10x + 73
Now the pipes length is 173 inches.
So:- 10x + 73 = 173
10x = 100
x = 10
So,
First piece = 10 inches
Second piece = 16 inches
Third piece = 147 inches
Hope this helps :-)
RELATED QUESTIONS
A 96 inch pipe is cut into 3 pieces. The second piece is seven inches shorter than the... (answered by checkley77)
A 29-inch piece of steel is cut into three pieces so that the second piece is twice as... (answered by math_tutor2020,ikleyn)
A 121 in. long pipe is cut into three pieces such that the second piece is five in. more... (answered by addingup)
A 30 inch piece of steel is cut into three pieces so that the second piece is twice as... (answered by josgarithmetic)
A 32-inch piece of steel is cut into three pieces so that the second piece is twice as (answered by Boreal,ikleyn)
A pipe is 48 inches long.Cut into three pieces so that the second piece is 1 inch less... (answered by edjones)
a 26-inch pieve of steel is cut into three pieces so that the second piece is twice as... (answered by mananth)
a 25 inch pieace of board is cut into three pieces so that the second piece is twice as... (answered by jessica43)
A 25 inch rope is cut into three pieces such that the middle sized piece is 1 inch longer (answered by solver91311)