SOLUTION: "Suppose the temperature outside is dropping at a constant rate. At noon, the temperature is 70 degrees f and it drops to 58 degrees at 5:00 p.m. How much did the temperature chang
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Question 99119: "Suppose the temperature outside is dropping at a constant rate. At noon, the temperature is 70 degrees f and it drops to 58 degrees at 5:00 p.m. How much did the temperature change each hour?
Found 2 solutions by checkley71, rcmcc:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
(70-58)/5=12/5=2.4 DEGREE DROP PER HOUR.
Answer by rcmcc(152) (Show Source): You can put this solution on YOUR website!
To solve this problem you need 2 pieces of data.
1. The amount of time that passes
2. The temperature drop over that amount of time
Because you measure the time from noon (12) to (5) there has been a 5 hour time difference.
to find the temperature change subtract 58 from 70 and you get 12 degrees.
now divide the temperature by the time
is your answer. in decimal form 2.4 degrees per hour.
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