SOLUTION: The weight-carrying capacity of a rectangular beam varies jointly with its width and the square of its height and inversely as its length. If a beam is 4 inches wide, 6 inches high
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Question 987358: The weight-carrying capacity of a rectangular beam varies jointly with its width and the square of its height and inversely as its length. If a beam is 4 inches wide, 6 inches high, and 10 feet long, it has a carrying capacity of 1400 pounds. Find the carrying capacity of a beam made of the same material if it is 3 inches wide, 5 inches high, and 12 feet long.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
W=k w*h^2/L
1400=k 4*36/10=k*14.4
k=100
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W=100*3*25/12=100* (75/12)=625 lb
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