Let the number of Nickels be x Let the number of Quarters be y Value Value Type Number of of of of EACH ALL coin coins coin coins ------------------------------------------- Nickels x $0.05 $0.05x Quarters y $0.25 $0.25y ------------------------------------------- TOTALS 25 ----- $3.85 The first equation comes from the second column.x + y = 25 The second equation comes from the last column: 0.05x + 0.25y = 3.85 Get rid of decimals by multiplying every term by 100: 5x + 25y = 385 So we have the system of equations: . We solve by substitution. Solve the first equation for y: x + y = 25 y = 25 - x Substitute (25 - x) for y in 5x + 25y = 385 5x + 25(25 - x) = 385 5x + 625 - 25x = 385 -20x + 625 = 385 -20x = -240 x = 12 = the number of Nickels. Substitute in y = 25 - x y = 25 - (12) y = 13 Quarters. The number of Quarters is 25-x or 25-12 or 13 Quarters. Checking: 12 Nickels is $0.60 and 13 Quarters is $3.25 That's 25 coins. And indeed $0.60 + $3.20 = $3.85 Edwin