SOLUTION: John can finish a work in 8days and peter can finish that same work in 6days.They worked together for 2days and peter left..How long will it take John to finish the work himself?

Question 979136: John can finish a work in 8days and peter can finish that same work in 6days.They worked together for 2days and peter left..How long will it take John to finish the work himself?
Found 2 solutions by josmiceli, ankor@dixie-net.com:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
John's rate of working is:
[ 1 job ] / [ 8 days ]
Peter's rate of working:
[ 1 job ] / [ 6 days ]
---------------------
Add their rates of working to
get their rate working together
Let = the fraction of the
job they finish working together
for 2 days

Multiply both sidfes by

That means there is
of the job remaining
----------------------
Let = time in days for John to
finish the job by himself

Multiply both sides by

John can finish the job in 3 and 1/3 days working alone
Hope I got it

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
John can finish a work in 8days and peter can finish that same work in 6days.
They worked together for 2days and peter left.
How long will it take John to finish the work himself?
:
let t = time for John to finish the job
let the completed job = 1
:
Peter works 2 days
John works (t+2) days
:
A shared work equation, each does a fraction of the job, the two fractions add up to 1
+ = 1
multiply equation by least common multiple, 24; cancel the denominators
3(t+2) + 4(2) = 24
3t + 6 + 8 = 24
3t = 24 - 14
t = 10/3
t = 3.33 additional hrs for John to finish the job (3 hrs 20 min)
:
:
Check this (John work a total of 5.33 hrs)
=
.667 + 333 = 1.0

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