SOLUTION: Find three consecutive even integers such that the product of the first and the third is 18 greater than the product of -1 and the third.

Question 952370: Find three consecutive even integers such that the product of the first and the third is 18 greater than the product of -1 and the third.
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
x=first x+2=second x+4=third
(x)(x+4)=((-1)(x+4))+18
Add x to each side.
Subtract 14 from each side.

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=81 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 2, -7. Here's your graph:

ANSWER 1: The first integer is 2.
x+2=2+2=4 ANSWER 2: The second integer is 4.
x+4=2+4=6 ANSWER 3: The third integer is 6.
CHECK:
(2)(6)=-1(6)+18
12=-6+18
12=12
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