SOLUTION: The cost of a long-distance phone call is $0.41 for the first minute and $0.30 for each additional minute. If the total charge for a long-distance call is $7.91, how many minutes w

Question 949246: The cost of a long-distance phone call is $0.41 for the first minute and $0.30 for each additional minute. If the total charge for a long-distance call is $7.91, how many minutes was the call?
Please help me! Help me find a solution with steps so that I know how to handle a math problem like this in the future. Thanks!
Found 2 solutions by macston, MathTherapy:
Answer by macston(5194) (Show Source): You can put this solution on YOUR website!
m=number of minutes of call; c=cost
c=$0.41+$0.30(m-1)
$7.91=$0.41+$0.30m-$0.30 combine like terms
$7.91=$0.30m+$0.11 Subtract $0.11 from each side.
$7.80=$0.30m Divide each side by $0.30.
26=m ANSWER: The call was 26 minutes
CHECK:
c=$0.41+$0.30(m-1)
$7.91=$0.41+$0.30(26-1)
$7.91=$0.41+$7.50
$7.91=$7.91

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
The cost of a long-distance phone call is $0.41 for the first minute and $0.30 for each additional minute. If the total charge for a long-distance call is $7.91, how many minutes was the call?
Please help me! Help me find a solution with steps so that I know how to handle a math problem like this in the future. Thanks!

Let number of minutes call lasted, be m
Then number of minutes used, at $0.30 is: m - 1
Therefore, C(m) = .3(m - 1) + .41
C(m) = .3m - .3 + .41
C(m) = .3m + .11
7.91 = .3m + .11 ------- Substituting 7.91 for C(m), or cost
.3m = 7.91 - .11
.3m = 7.8
m, or minutes call lasted = , or
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