SOLUTION: Eric gave away 2/3 of his fish. He then gave away 3/5 of his remaining fish. He was left with 30 fish. How many did he start with?

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Question 934853: Eric gave away 2/3 of his fish. He then gave away 3/5 of his remaining fish. He was left with 30 fish. How many did he start with?
Found 3 solutions by vicgonzerx, josgarithmetic, MathTherapy:
Answer by vicgonzerx(31)   (Show Source): You can put this solution on YOUR website!
x=total fish eric had
(x-2/3x)-3/5(x-2/3x)=30
x=225 fish is the answer
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
q, original number of fish.


first give-away.
, the second give-away.








LCD is , so multiply left and right by this.












Mistakes are easily made in this solution. Watch signs and factors carefully.
Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Eric gave away 2/3 of his fish. He then gave away 3/5 of his remaining fish. He was left with 30 fish. How many did he start with?
If  of fish is given away, then  is left

Giving away  of remainder leaves  of remainder, or , or 

Let original number of fish be N

Now, since 30 remained after the giveaways, which is also represented by , then we can say that:  

 ------ Cross-multiplying

2N = 450

N, or original number of fish = , or 

You can do the check!! 

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