SOLUTION: John made a rectangular pen for his dog using 28 feet of fencing. If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen?

Question 93349: John made a rectangular pen for his dog using 28 feet of fencing.
If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen?
Found 2 solutions by checkley75, praseenakos@yahoo.com:
Answer by checkley75(3666) (Show Source): You can put this solution on YOUR website!
W=L/2+2
2W+2L=28
2(L/2+2)+2L=28
L+4+2L=28
3L=28-4
3L=24
L=24/3
L=8 ANSWER FOR THE LENGTH.
W=8/2+2
W=4+2
W=6 ANSWER FOR THE WIDTH
PROOF
2*8+2*6=28
16+12=28
28=28

Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
Question:
John made a rectangular pen for his dog using 28 feet of fencing.
If the width of the pen is 2 feet more than one-half the length, what are the length and width of the pen?

Answer:
Given data:
* Recangular Pen
* 28 feet fencing ==> perimeter of the rectangle is 28 feet.
* width of the pen is 2 feet more than one-half the length.

Let us assume that , length = x feet.

One half of the length =

2 feet more than one-half the length = + 2

Therefore, width = + 2

Perimeter of the rectangle is given by the formula,

P = 2 (length + width)

==> 28 = 2 ( x + + 2 )

Divide throughout the expression by 2

==> 14 =

Again multiply throughout by 2.

==>

==>

==>

Subtract 4 from both sides....

==> 28 - 4 = 3x + 4 - 4

==> 24 = 3x

Divide both sides by 3

==>

==> 8 = x

That is length = 8 feet

Therefore, width =

==> width 4 + 2 = 6 feet.

Hence the answer.

Hope ypou found the explanation useful.

Regards.

Praseena.

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