# SOLUTION: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.

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 Question 93156: Three consecutive even integers are such that the square of the third is 76 more than the square of the second. Find the three integers.Answer by checkley75(3666)   (Show Source): You can put this solution on YOUR website!(x+4)^2=(x+2)^2+76 X^2+8x+16=x^2+4x+4+76 8x-4x=80-16 4x=64 x=64/4 x=16 answer for the first number. 16+2=18 for the middle number . 16+4=20 for the highest number. proof 20^2=18^2+76 400=324+76 400=400