SOLUTION: How much 12% acid solution and pure water must be mixed to produce 228 gallons of a mixture that is 7% acid?

Question 928998: How much 12% acid solution and pure water must be mixed to produce 228 gallons of a mixture that is 7% acid?

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
x = 12% acid = 88% water
y = 100% water
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7% acid = 93% water
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88x + 100y = 93(x + y)
x + y = 228
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put the system of linear equations into standard form
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88x + 100y = 93*228
x + y = 228
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88x + 100y = 21204
x + y = 228
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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answer:
x = 12% acid = 133 gal
y = 100% water = 95 gal
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