SOLUTION: if the length of a skating rink is 20 meters greater than twice the width and the area is equal to 6000 meters squared, what is the width of the skating rink?

Question 925608: if the length of a skating rink is 20 meters greater than twice the width and the area is equal to 6000 meters squared, what is the width of the skating rink?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
L = 2w + 20
Lw = 6000
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Lw = 6000
(2w + 20)w = 6000
2ww + 20w - 6000 = 0
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the above quadratic equation is in standard form, with a=2, b=20 and c=-6000
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
2 20 -6000
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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w = 50
w = -60
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the negative root doesn't fit the problem statement, so use the positive root:
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answer:
w = 50 m
L = 120 m
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Solve quadratic equations, quadratic formula:
https://sooeet.com/math/quadratic-formula-solver.php
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