SOLUTION: Two natural numbers differ by two units and the sum of thier sqaures is 580. What are these numbers?
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Question 921256: Two natural numbers differ by two units and the sum of thier sqaures is 580. What are these numbers?
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Two natural numbers differ by two units and the sum of thier sqaures is 580. What are these numbers?
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Equations:
x - y = 2
x^2 + y^2 = 580
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Substitute for "x" and solve for "y";;
(y+2)^2 + y^2 = 580
y^ + 4y + 4 + y^2 = 580
y^2 + 2y + 2 = 290
y^2 + y - 288 = 0
y = 16
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Therefore, x = 18
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Cheers,
Stan H.
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Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
x^2 + (x-2)^2 = 580
2x^2 - 4x + 4 - 580 = 0
x^2 - 2x -288 = 0
(x - 18)(x+16) = 0
x = -16, 18
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