SOLUTION: show the equation used for the solution.
In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each cand
Algebra.Com
Question 92115: show the equation used for the solution.
In a town election, the winning candidate had 220 more votes than the loser. If 810 votes were cast in all, how many votes did each candidate receive?
Answer by anraymer(35) (Show Source): You can put this solution on YOUR website!
T = A + B
T = 810
A = 220 + B
810 = (220 + B) + B
810 = 220 + 2B
590 = 2B
295 votes = B
A = 220 + B
A = 220 + 295
A = 515 votes
RELATED QUESTIONS
Social Science. Show the equation used for the solution. In a town election, the... (answered by jim_thompson5910)
Show the equation used for the solution
In a town election, the winning candidate had... (answered by stanbon)
Solve the following problems.show the equation used for the solution.
Social science. (answered by ptaylor)
In a town election, the winning candidate had 220 more votes than the loser. If 810 votes (answered by checkley71)
In a town election, the winning candidate had 220 more votes
than the loser. If 810... (answered by Nate)
In a town election, the winning candidate had 220 more votes than the loser. If 810... (answered by josmiceli)
In a town election, the winning candidate had 220 more votes than the loser. If 810... (answered by faceoff57)
In a town election, the winning candidate had 220 more votes than the loser. If 810 votes (answered by uma)
In a town election, the winning candidate had 220 more votes
than the loser. If 810... (answered by Nate)