SOLUTION: Larry invested part of his 17,000 advance at 6% annual simple interest and the rest at 9% if his total yearly interest from both accounts was $1320 find the amount invested at each
Algebra.Com
Question 916691: Larry invested part of his 17,000 advance at 6% annual simple interest and the rest at 9% if his total yearly interest from both accounts was $1320 find the amount invested at each rate
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
x amount at 9%
.09x + .06(17000-x) = $1320
x = (1320- 1020)/.03 = $10,000 at 9%,
$7000 at 6%
RELATED QUESTIONS
Larry Mitchell invested part of his $30,000 advance at 5% annual simple interest and the... (answered by greenestamps)
Larry Mitchell invested part of his $17,000 advance at 6% annual simple interest and the... (answered by richwmiller)
Larry mitchel invested part of his $13,000 advance at 7% annual simple interest and the... (answered by ikleyn,greenestamps)
Larry MItchell invested part of his $17,000 advance at 6% annual simple interest and the... (answered by richwmiller)
Larry Mitchell invested part of his
$16,000
advance at
5%
annual simple interest... (answered by ewatrrr)
larry mitchell invested part of his 13,000 advance at 6% annual simple interest and the... (answered by richwmiller)
Larry Mitchell invested part of his
$ 17 comma 000$17,000
advance at
4 %4%
annual (answered by Boreal)
Larry Mitchell invested part of his $30000 advance at 3% annual interest and the rest at... (answered by ewatrrr)
Larry Mitchell invested part of his $30000 advance at 3% annual interest and the rest at... (answered by addingup)