SOLUTION: The perimeter of a rectangula town is 24m.if the are of the town is 35cm^2,how wide is the town?

Question 912085: The perimeter of a rectangula town is 24m.if the are of the town is 35cm^2,how wide is the town?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangula town is 24m.if the are of the town is 35cm^2,how wide is the town?
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P = 2W + 2L = 24m = 2400 cm
W + L = 1200
W*L = 35
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W + L = 1200 --> L = 1200 - W
---
W*L = 35
W*(1200 - W) = 35
W^2 - 1200W + 35 = 0

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=1439860 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 1199.97083262439, 0.0291673756131559. Here's your graph:

===========================
W = 0.029167 cm

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