SOLUTION: Bob owns a watch repair shop. He has found that the cost of operating his shop is given by c(x)=4x^2-304x+71, where x is the number of watches repaired. How many watches must her r

Question 91099: Bob owns a watch repair shop. He has found that the cost of operating his shop is given by c(x)=4x^2-304x+71, where x is the number of watches repaired. How many watches must her repair to have the lowest cost?
Thanks.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Bob owns a watch repair shop. He has found that the cost of operating his shop is given by c(x)= 4x^2 - 304x + 71, where x is the number of watches repaired. How many watches must he repair to have the lowest cost?
:
find the axis of symmetry, using the formula: x = -b/(2a)
In the above equation a = 4; b = -304
:
x = -(-304)/(2*4)
x = +304/8
x = +38 is the number of watches for lowest cost
:

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