SOLUTION: A ball is thrown upward with an initial velocity of 48 feet per second from a height of 864 feet. Its height h in feet after t seconds is given by h(t) =-16t^2+48t+864 after how lo
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Question 909873: A ball is thrown upward with an initial velocity of 48 feet per second from a height of 864 feet. Its height h in feet after t seconds is given by h(t) =-16t^2+48t+864 after how long will the ball reach the ground.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
h(t) =-16t^2+48t+864
0 = -16t^2+48t+864
0 = -16(x-3/2)^2 + 36 + 864
16(x-3/2)^2 = 900
x = 3/2 + 15/2= 9sec
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