SOLUTION: The height of a ball that is thrown upward is given by h(t) = {{{ 16t^2 + 68t }}} where t is in seconds and height is in feet. The maximum height the ball reaches is ____ f

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Question 906158: The height of a ball that is thrown upward is given by
h(t) =
where t is in seconds and height is in feet. The maximum height the ball reaches is ____ feet, when t = ____ seconds.

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
The equation should be:

The minus sign is for the
downward pull of gravity
-----------------------
The formula for
is:

where:




Now find
---------------------



--------------------
The max height is 72.25 ft
when the time is 2.125 sec
-------------------------
Here's the plot:




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