SOLUTION: A ball is thrown up at the edge of a 376 foot cliff. The ball is thrown up with an initial velocity of 117 feet per second.
Its height measured in feet is given in terms of tim
Algebra.Com
Question 904236: A ball is thrown up at the edge of a 376 foot cliff. The ball is thrown up with an initial velocity of 117 feet per second.
Its height measured in feet is given in terms of time t, measured in seconds by the equation
h = -16 t^2 + 117 t + 376
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A ball is thrown up at the edge of a 376 foot cliff. The ball is thrown up with an initial velocity of 117 feet per second.
Its height measured in feet is given in terms of time t, measured in seconds by the equation
h = -16 t^2 + 117 t + 376
------------
That seems reasonable.
Don't put spaces after the coefficients, tho.
h = -16t^2 + 117t + 376
RELATED QUESTIONS
A ball is thrown up at the edge of a 274 foot cliff. The ball is thrown up with an... (answered by solver91311)
A ball is thrown upward with an initial velocity of 80 feet per second from the edge of a (answered by ankor@dixie-net.com)
A ball is thrown vertically upward from the ground with an initial velocity of 103 feet... (answered by ikleyn)
A ball is thrown straight up from the top of a building 128 ft tall with an initial... (answered by ewatrrr)
A ball is thrown downward from the top of a 130-foot building with an initial... (answered by Alan3354)
The height in feet above the ground of a ball thrown straight up with an initial velocity (answered by rajagopalan)
A ball is thrown vertically upward from the ground with an initial velocity of 103 feet... (answered by ikleyn)
A ball is thrown vertically upward from the top of a building 112 feet tall with an... (answered by Solver92311)
Please help me solve this equation:
A ball is thrown upward with an initial velocity... (answered by KnightOwlTutor)