SOLUTION: If two opposite sides of a square are increased by 12 meters and the other sides are decreased by 6 meters, the area of the rectangle that is formed is 63 square meters. Find the a

Question 902771: If two opposite sides of a square are increased by 12 meters and the other sides are decreased by 6 meters, the area of the rectangle that is formed is 63 square meters. Find the area of the original square.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If two opposite sides of a square are increased by 12 meters and the other sides are decreased by 6 meters, the area of the rectangle that is formed is 63 square meters. Find the area of the original square.
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Equation:
(s+12)(s-6) = 63
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s^2 + 6s - 72 = 63
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s^2 + 6x - 135 = 0
Factor::
(s-9)(s+15) = 0
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Positive solution::
s = 9 meters
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Original area:: s^2 = 81 sq meters
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Cheers,
Stan H.
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