SOLUTION: How much of a(n) 90% orange juice drink must be mixed with 16 gallons of 30% orange juice drink to obtain a mixture that is 50% orange juice?

Question 901175: How much of a(n) 90% orange juice drink must be mixed with 16 gallons of 30% orange juice drink to obtain a mixture that is 50% orange juice?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How much of a(n) 90% orange juice drink must be mixed with 16 gallons of 30% orange juice drink to obtain a mixture that is 50% orange juice?
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Equation::
orange + orange = orange
0.90x + 0.30*16 = 0.50(x+16)
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90x + 30*16 = 50x + 50*16
40x = 20*16
x = (1/2)16
x = 8 gallons (amt. of 90% juice needed)
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Cheers,
Stan H.
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