SOLUTION: A boat traveled downstream a distance of 52 mi and then came right back. If the speed of the current was 5 mph and the total trip took 4 hours and 20 minutes, find the average spee

Question 900323: A boat traveled downstream a distance of 52 mi and then came right back. If the speed of the current was 5 mph and the total trip took 4 hours and 20 minutes, find the average speed of the boat relative to the water.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi

52/(r+5) + 52/(r-5) = 13/3

 52(r-5) + 52(r+5) = 13/3(r^2 - 25)

  104r = (13/3)(r^2-25)

  13r^2 -312r - 13*25 = 0

 r^2 - 24r - 25 = 0 

(r +1)(r-25) = 0,  r = 25mph

 

RELATED QUESTIONS

A boat traveled downstream a distance of 85 mi and then came right back. If the speed of... (answered by josgarithmetic)
A boat traveled downstream a distance of 36 mi and then came right back. If the speed of... (answered by josmiceli)
A boat traveled downstream a distance of 152 mi and then came right back. If the speed of  (answered by excellentsolutionas)
A boat traveled downstream a distance of 65 mi and then came right back. If the speed of... (answered by josmiceli)
A boat traveled downstream a distance of 50 mi and then came right back. If the speed of... (answered by josgarithmetic,Boreal,josmiceli,MathTherapy)
A boat traveled downstream a distance of 36 mi and then came right back. If the speed of... (answered by ikleyn,josgarithmetic)
	  
A boat traveled downstream a distance of 90 mi and then came right back. If the... (answered by josgarithmetic,ikleyn)
A boat traveled downstream a distance of 128mi and then came right back.  If the speed of  (answered by lwsshak3)
A boat traveled downstream a distance of 44 miles and then came right back. If the speed... (answered by josgarithmetic)