SOLUTION: Hi, could you please help me on a problem that I have. I do not need to solve this problem, I just need to put it into an equation. This is the problem: The height of a tower is th

Question 8985: Hi, could you please help me on a problem that I have. I do not need to solve this problem, I just need to put it into an equation. This is the problem: The height of a tower is three times the height of a certain building. If the tower is 50 m taller than the building, how tall is the tower?
I tried to work out the problem: I used b for my variable. Then I used 3b for the tower height, and b for the building height (I'm in the beginning of Algebra 1, so we are suppose to use only 1 variable).
Then I put together this equation: 3b - b = 50 m. Could you please tell me if this is right, and also add how you get it? Thank you so much!!
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
It looks right to me. To finish, just solve the equation:
3b - b = 50

Remember that b = 1b, so 3b - 1b = 2b
2b = 50
b= 25 feet= height of the building
3b = 75 feet = height of the tower.

Check: You said that the tower is supposed to be 50 feet taller than the building, which indeed it is!! So you got it right, and it checks! Nice work!!

R^2 at SCC
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