SOLUTION: weights of 40 lbs . and 50 lbs. are placed on opposite sides of the fulcrum and they balance . If one weight is a foot nearer the fulcrum than the other , where is each weight plac
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Question 88801:  weights of 40 lbs . and 50 lbs. are placed on opposite sides of the fulcrum and they balance . If one weight is a foot nearer the fulcrum than the other , where is each weight placed? 
Answer by malakumar_kos@yahoo.com(315)   (Show Source): You can put this solution on YOUR website!
 
    weights of 40 lbs . and 50 lbs. are placed on opposite sides of the fulcrum and they balance . If one weight is a foot nearer the fulcrum than the other , where is each weight placed?
      Let the weight of 50 pounds be placed at a distance  of x  units from the fulcrum 
        Then the weight of 40 pounds is placed at a distance of (x-1) units 
  from the fulcrum
      using the concept of order of levers we get 50*(x-1) = 40x
                                                  50x-50 = 40x
                                                   50x-40x = 50
                                                       10x = 50
                                                         x = 50/10  = 5
      Therefore 50 pounds must be placed at a distance of 5 units and 40 pounds 
      must be placed at a distance of 5-1 = 4 units from the fulcrum. 
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