You can
put this solution on YOUR website!The equation is based upon the fact that "Her weight is equal to 60 lbs. plus half her weight."
Srart by letting x = thw weight of the woman (if she is like most women I know, in this case, x is REALLY the unknown!)
"Her weight is equal to 60 lbs. plus half her weight."
You probably don't like that fraction, so just multiply both sides of the equation by 2 and get rid of it.
Subtract x from each side, and you get:
Check it out: Her weight is 120, which equals 60 plus half of her weight, which is another 60.
You might figure out a way to do this intuitively (like in your head), but I like equations. They are reliable!
R^2 at SCC
You can
put this solution on YOUR website!Say that her weight is that mysterious W. If she says that her weight is 60 pounds plus 1/2 of her weight, that's

<-------------- Start here

<---- subtract 0.5W from both sides

<----- combine like terms

<----- divide both sides by 0.5. She weighs 120 pounds.