SOLUTION: A vessel contains 20% solution of acetic acid and another vessel contains 50% solution of acetic acid. Mang Luis needs 300cc of 30% acetic acid. How many cc of each solution must h

Question 886381: A vessel contains 20% solution of acetic acid and another vessel contains 50% solution of acetic acid. Mang Luis needs 300cc of 30% acetic acid. How many cc of each solution must he mix?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A vessel contains 20% solution of acetic acid and another vessel contains 50% solution of acetic acid. Mang Luis needs 300cc of 30% acetic acid. How many cc of each solution must he mix?
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Equation:
acid + acid = acid
0.20x + 0.50(300-x) = 0.30*300
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20x + 50*300 - 50x = 30*300
-30x = -20*300
x = (2/3)300 = 200cc (amt. of 20% solution needed)
300-x = 100cc (amt of 50% solution needed)
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Cheers,
Stan H.
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