SOLUTION: How Can I Translate the following statements into inequalities.
and use x to represent please help?
The cost for a long-distance telephone call is $0.36 for the first min
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Question 88092: How Can I Translate the following statements into inequalities.
and use x to represent please help?
The cost for a long-distance telephone call is $0.36 for the first minute and $0.21 for each additional minute or portion thereof. Write an inequality representing the number of minutes a person could talk without exceeding $3
Found 2 solutions by tutor_paul, jenna1026:
Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!
Let's try to think this through rather than just write down the answer :-)
Reading the problem, the first thing I see is that the goal is to keep the
cost less than $3. This immediately tells me that I will use the < (less than)
symbol in my inequality, and however long I talk, the cost must be less than
$3. So I can write this part of the inequality:
---------------------
something < $3
---------------------
Now, we need to figure out what is that "something."
Reading the problem, I see that the first minute of talking is going to cost me
$0.36. The first minute only happens once per call. So $0.36 is part of the
"something." With this information, I can make the inequality a little more
informative:
-----------------------------
$0.36 + something_else < $3
-----------------------------
So, we are up to that "something else." Again, from the problem, you are told that the cost after the first minute is $0.21 per minute. That implies a multiplication... i.e. every minute you talk costs $0.21. If you let 'x' equal
the number of minutes, you can see that the "something_else" is $0.21x. So now,
my inequality is done!
-------------------
$0.36+$0.21x < $3
-------------------
Good Luck,
tutor_paul@yahoo.com
Answer by jenna1026(3) (Show Source): You can put this solution on YOUR website!
cost = 0.36 + 0.21(min-1)
3 > .36 + .21m - .21
3 > .15 + .21m
Subtract .15:
2.85 > .21m
13.57 > m
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