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put this solution on YOUR website!Let the cost per day for the room be $x and that of the car be $y.
As per the first plan, 3x+2y = 360
As per the second plan, 4x+3y = 500
So the system of equations are
3x+2y = 360 -------------(1)
4x+3y = 500 -------------(2)
This is going to be solved by elimination.
(1) times 3 gives, 9x+6y = 1080
(2) times 2 gives, 8x+6y = 1000
Subtracting the above 2 equations, x = 80
Plugging in this value in (1),
3(80)+2y = 360
240+2y = 360
==> 2y = 360 - 240
==> 2y = 120
==> y = 60
Thus the cost of a room per day is $80 and that for a car is $60