SOLUTION: the of a rectangle is 4 feet less than twice the width.the area is 160 squ the are feet. find the length andd width of the rectangle and diagonal

Question 866379: the of a rectangle is 4 feet less than twice the width.the area is 160 squ the are feet. find the length andd width of the rectangle and diagonal
Found 2 solutions by josgarithmetic, ewatrrr:
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
---from description
-----ready to find w.

Note that the diagonal cuts the rectangle into two congruent (equal size and shape) right triangles.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi
A = Lw = (2w-4)w = 160
w^2 -2w - 80 = 0
(w + 8)(w-10) = 0 (Tossing out the negative solution for unit measure)
w = 10ft and L = 16ft
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