SOLUTION: The volume of cube is increasing at 20.0 cm^3/min. At the instant when its volume is 729 cm^3, what is the rate of change of its edge? Round the answer to 3 decimal places.

Question 860001: The volume of cube is increasing at 20.0 cm^3/min. At the instant when its volume is 729 cm^3, what is the rate of change of its edge? Round the answer to 3 decimal places.

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The volume of cube is increasing at 20.0 cm^3/min. At the instant when its volume is 729 cm^3, what is the rate of change of its edge? Round the answer to 3 decimal places.
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V = s^3

ds/dt = (1/3)*V^(-2/3)*dV/dt
ds/dt = (1/3)*729^(-2/3)*20
ds/dt = (20/3)/81 = 20/243
ds/dt =~ 0.0823 cm/min
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