SOLUTION: Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as

Question 85225: Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
� 16 represents �g, the gravitational pull due to gravity (measured in feet per second 2).
� v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
� s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
a) What is the function that describes this problem?
b) The ball will be how high above the ground after 1 second?
c) How long will it take to hit the ground?
d) What is the maximum height of the ball?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t.
This function is s = -16t2 + v0t + s0
� 16 represents �g, the gravitational pull due to gravity (measured in feet per second 2).
� v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
� s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
a) What is the function that describes this problem?
s(t) = -16t^2+32t+0
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b) The ball will be how high above the ground after 1 second?
Find s(1)
-----------------
c) How long will it take to hit the ground?
Let s(t) = zero and solve for t
------------------------
d) What is the maximum height of the ball?
Maximum occurs at t = -b/2a = -32/(2(-16) = 1
Part "b" told you what s(1) was; that is the max.
==============
Cheers
Stan H.

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