SOLUTION: 15 men take 21 days of 8 hrs. each to do a piece of work.How manydays of 6 hrs. each would it take for 21 women if 3 women do as much work as 2 men? (a) 30 (b) 20 (c) 19 (d)

Question 851246: 15 men take 21 days of 8 hrs. each to do a piece of work.How manydays of 6 hrs. each would it take
for 21 women if 3 women do as much work as 2 men?
(a) 30
(b) 20
(c) 19
(d) 29

Answer by JulietG(1812) (Show Source): You can put this solution on YOUR website!
21 days * 8 hours = 168. Multiply that by 15 men to get 2520 man-hours for this project.
The women in this equation work at the rate of 2/3 of the men. They'll need to have 2520 * 3/2 man-hours to equal the men. 2520*3/2= 3780 man-hours. Divide those hours among 21 women to get 3780/21 = 180. They're only working 6 hours. Divide 180 by 6 to get 180/6=30 days.
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